If in the previous problem, particle `A` moves with constant acceleration `4 m//s^(2)` with initial speed `5 m//s` and `B` moves with uniform speed `12 m//s`, when and where the particle meet?

If in the previous problem, particle `A` moves with constant accelerat

1.	If in the previous problem, particle `A` moves with constant acceleration `4 m//s^(2)` with initial speed `5 m//s` and `B` moves with uniform speed `12 m//s`, when and where the particle meet?
Answer» For `A:d =5t+1/2xx4t^(2)` `=5t+2t^(2)` (accelerated motion) …(i) For `B: 100-d=12t` (uniform motion) …(ii) Adding (i) and (ii), we get `100=2t^(2)+17t` `2t^(2)+17t-100=0` `t=(-17+-sqrt((17)^(2)+4(2)(-100)))/(2xx2)` `=(-17+-sqrt(289+800))/4` `=(-17+-33)/4=4 s, d=52m`

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If in the previous problem, particle `A` moves with constant acceleration `4 m//s^(2)` with initial speed `5 m//s` and `B` moves with uniform speed `12 m//s`, when and where the particle meet?

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