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If `int(2^(1//x))/(x^(2))dx=a2^(1//x)+C`, then a=A. `-log_(2)e`B. `-log_(e)2`C. `-1`D. `1//2` |
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Answer» Correct Answer - a `int(2^(1//x))/(x^(2))dx=-int2^(1//x)d((1)/(x))=(-2^(1//x))/(log_(e)2)+C=-(log_(2)e)2^(1//x)+C` `:. a=-log_(2)e` |
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