1.

If K_(c) is the equlibrium constant for the formation of KH_(3). the dissociation constant of ammonia under the same temperaturee will be

Answer»

`K_(c)`
`sqrtK_(c)`
`K_(c)^(2)`
`1//K_(c)`

Solution :`NH_(3)hArr1/2N_(2) +3/2H_(2)`
`K_(c)=([N_(2)]^(1//2)[H_(2)]^(3//2))/(NH_(3))and 1/2N_(2)+3/2H_(2)hArrNH_(3)`
`K_(c)=([NH_(3)])/([N_(2)]^(1//2)[H_(2)]^(3//2))`


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