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If kinetic energy of a body is increased by 300%, then percentage change in momentum will beA. `100%`B. `150%`C. `265%`D. `73.2%` |
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Answer» Correct Answer - A `P_1=sqrt(2mE_1) , P_2=sqrt(2mE_2)` `=sqrt(2m(E_1+300/100E_1))=sqrt(2m(4E_1))=2P_1` % change `=(P_2-P_1)/P_1xx100=(2P_2-P_1)/P_1xx100=100%` |
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