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If l is the length, A is the area of cross-section and K the thermal conductivity, then the thermal resistance of the block is given byA. `(Kl)/(A)`B. `(l)/(KA)`C. `(AK)/(l)`D. `(A)/(Kl)` |
Answer» Correct Answer - B `Q=(KA(theta_(1)-theta_(2)))/(l) or Q/l = (theta_(1)-theta_(2))/(l//KA)` Compare with `I = V/R` So, thermal resistance = `l/(KR)`. |
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