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If L1 and L2 are the inductance used in the Hartley oscillator, the effective inductance in the equation of frequency calculation is equal to (Without considering mutual inductance).(a) (L1×L2)/(L1+L2)(b) L2^2/(L1+L2)(c) L1+L2(d) L1-L2This question was posed to me in exam.My query is from Hartley Oscillator-2 in portion Oscillators of Analog Circuits

Answer»

Correct answer is (c) L1+L2

Easiest explanation: INDUCTANCE L1 and L2 are SERIES and hence effective inductance WITHOUT MUTUAL inductance will be L1+L2.



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