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If lambda is decay constant of a nucleus, find the probability that a nucleus will decay in time t and further will not decay in time t: |
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Answer» `(1-e^(lambdat))^(-1), e^(-lambdat)` `=N_(0) (1-e^(-lambda t)` Probability that ATOM decays in time `t=("Number of atoms decayed")/("Total number of the atoms")` `=(N_(0) (1-e^(-lambda t)))/(N_(0))` `=1-e^(-lambda t) ..........(1)` Probability that an atom will not decay in time `t=1-(1-e^(-lambdat))` `=e^(-lambda t) ..........(2)` |
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