If `lambda_(max)` is `6563 Å`, then wave length of second line of Balmer series will beA. `lambda = (16)/(3R)`B. `lambda = (36)/(5R)`C. `lambda = (4)/(3R)`D. None of the above

If `lambda_(max)` is `6563 Å`, then wave length of second line of Bal

1.	If `lambda_(max)` is `6563 Å`, then wave length of second line of Balmer series will beA. `lambda = (16)/(3R)`B. `lambda = (36)/(5R)`C. `lambda = (4)/(3R)`D. None of the above
Answer» Correct Answer - A For Balmer series `(1)/(lambda) = R ((1)/(2^(2)) - (1)/(n^(2)))` where `n = 3, 4, 5` For second line `n = 4` So `(1)/(lambda) = R ((1)/(2^(2)) - (1)/(4^(2))) = (3)/(16) R rArr lambda = (16)/(3R)`

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If `lambda_(max)` is `6563 Å`, then wave length of second line of Balmer series will beA. `lambda = (16)/(3R)`B. `lambda = (36)/(5R)`C. `lambda = (4)/(3R)`D. None of the above

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