1.

If Lamda_(NaOAc)^(@)=91 and Lamda_(HCl)^(@)=496.2" S "cm^(2)mol^(-1) then what is required to find out Lamda_(HOA c)^(@) ?

Answer»

`Lamda_(ClCH_(2)COOH)`
`Lamda_(CH_(3)COOH)`
`lamda_(H+)^(@)`
`Lamda_(NaCl)^(@)`

Solution :`Lamda_(NaAc)^(@)=(Lamda_(NaAc)^(@)+Lamda_(HCl)^(@))-(Lamda_(NaCl)^(@))`
i.e., by KNOWING the value of `^^_(NaCl)^(@)`, we can DETERMINE `^^_(HOA C)^(@)`.


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