1.

If lamdaClCH_(2)COONa=224Ohm^(-1)cm^(2)gm" "equ^(-1),lamdaNaCl=38.2Ohm^(-1)cm^(2)" gm "equ^(-1) and lamdaHCl=203Ohm^(-1)cm^(2)" gm "equ^(-1), then what is the value of lamdaClCH_(2)COOH ?

Answer»

`288.5Ohm^(-1)cm^(2)" gm "EQU^(-1)`
`289.5Ohm^(-1)cm^(2)" gm "equ^(-1)`
`388.5Ohm^(-1)cm^(2)" gm "equ^(-1)`
`59.5Ohm^(-1)cm^(2)" gm "equ^(-1)`

SOLUTION :`lamdaClCH_(2)COOH`
`=lamdaClCH_(2)COONa+lamdaHCl-lamdaNaCl`
`=224+203-38.2`
`=388.8Ohm^(-1)cm^(2)" gm "equ^(-1)`.


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