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if letters of the word MATHEMATICS are arranged then the probability that C come before E,E before H ,H before I and I before SA. `(1)/(75)`B. `(1)/(24)`C. `(1)/(120)`D. `(1)/(720)` |
Answer» Correct Answer - C `(c )` The total number of arrangments is `(11!)/(2!2!2!)=(11!)/(8)` The number of arrangements in which `CE,H,I,S` appear in that order `"^(11)C_(5)(6!)/(2!2!2!)=(11!)/(8*5!)` `:.` Required Proability `=((11!)/(8*5!))/((11!)/(8))=(1)/(120)` |
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