1.

If line `3x-ay-1=0` is parallel to the line `(a+2)x-y+3=0` then find the values of a.

Answer» The slope of the line `3x-ay-1=0` is `3//a`. The slope of the line `(a+2)x-y+3=0` is `a+2`.
Since the lines are parallel, we have
`a+2(3)/(a)`
or `a^2+2a-3=0`
or `(a-1)(a+3)=0`
or `a=1or a=-3`.


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