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If linear velocity of a body moving on the circumference of a circle be equal to the velocity acquired by a freely falling body by a distance equal to half of the radius of the circle, show that centrepetal acceleration is equal to the acceleration due to gravity. |
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Answer» SOLUTION :The magnitude of the velocity ACQUIRED by a FREELY falling BODY through distance (r/2) is V= `sqrt(2gxxr/2)=sqrt(gr)` The centripetal acceleration is `v^2/r=gr/r=g` |
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