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If log3 [log2 (log3 x)] = 1, show that x = 6561. |
Answer» log3 [log2 (log3 x)] = 1 ∴ log2 (log3 x) = 31 ∴ log3 x = 23 ∴ log3 x = 8 ∴ x = 38 ∴ x = 6561 |
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