InterviewSolution
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InterviewSolution
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If M is molecular of solvent, `K_(b)` is molal elevation constant, `T_(b)` is its boiling point, `P^(@)` is its vapour pressure at temperature T and `P_(s)` is vapour pressure of its solution having a non-volatile solute at T K, thenA. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xxM`B. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b)xxM)`C. `(p^(@)-p_(s))/(p^(@))=(K_(b))/(T_(b))xx(M)/(1000)`D. `(p^(@)-p_(s))/(p^(@))=(DeltaT_(b))/(K_(b))xx(M)/(1000)` |
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Answer» Correct Answer - D `(p^(@)-p_(s))/(p^(@))=(n)/(N)=("Molality"xxM)/(1000)` `"and " "molality"=(DeltaT_(b))/(K_(b))" " (becauseDeltaT_(b)=K_(b)xxm)` |
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