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If m sin teta + n cos teta =p and m cos teta - n sin teta =q then prove m² + n² =p²+q² |
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Answer» -step explanation:SQUARE on both SIDES of p as well as q, then add that will become, m²(sin²A+cos²A)+n²(cos²A+sin²A) +2mnsinAcosA - 2nmsinAcosA = p²+q²m²(1)+n²(1) = p²+q²m²+n²=p²+q² |
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