If marks of A is 20% more than that of B. Then, marks of B is how much

1.	If marks of A is 20% more than that of B. Then, marks of B is how much percent less that of A.1. 34.56%2. 17.86%3. 17.89%4. 16.66%
Answer» Correct Answer - Option 4 : 16.66% Given: Marks of A = Marks of B + 20% marks of B Calculation: Let the B’s marks is x A’s marks = 20% of x + x ⇒ 120x/100 Required percentage = {[(120x/100) - x]/[115x/100]} × 100 ⇒ {[(20x/100)]/[(120x/100)]} × 100 ⇒ 16.66% Alternate method: If A is x% more than B, then B is {[(x)/(100 + x)] × 100}% less than A. ⇒ [(20/120) × 100]% ⇒ 16.66%

If marks of A is 20% more than that of B. Then, marks of B is how much percent less that of A.1. 34.56%2. 17.86%3. 17.89%4. 16.66%

Answer» Correct Answer - Option 4 : 16.66%

Given:

Marks of A = Marks of B + 20% marks of B

Calculation:

Let the B’s marks is x

A’s marks = 20% of x + x

⇒ 120x/100

Required percentage = {[(120x/100) - x]/[115x/100]} × 100

⇒ {[(20x/100)]/[(120x/100)]} × 100

⇒ 16.66%

Alternate method:

If A is x% more than B, then B is {[(x)/(100 + x)] × 100}% less than A.

⇒ [(20/120) × 100]%

⇒ 16.66%

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If marks of A is 20% more than that of B. Then, marks of B is how much percent less that of A.1. 34.56%2. 17.86%3. 17.89%4. 16.66%

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