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If mass of a planet is eight times themass of the earth and its rodius istwice the radius of the earth, whtwill be the escape velocity for thaplanet?Ans : 22.4 km/s

Answer»

Planet mass is 8 times that earthPlanet radius is twice then the radius of earth.Let mass of the Earth = MRadius of the Earth = R

Now, we know that The equation to get escape velocity

v = √(2 g r)

V = root(2GM)/R

If the mass of planet is eight times then escape velocity = 2 √2 times.

Escape velocity reduced to by 1/√2. If radius expands twiceHence the net escape velocity will be increase.

2 √2 × (1/√2)= 2 times now.Now it is clear that the escape velocity of that planet will be 2 times from the earth.

Escape velocity of the earth = 11.2 km/sEscape velocity of that planet = 2× 11.2= 22.4 km/sec.

Hence the escape velocity of that planet will be 22.4 km/s

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