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If matrix `A=[(a,b),(c,d)]`, then `|A|^(-1)` is equal toA. ad-bcB. `(1)/(ad-bc)`C. `(1)/(ad-bc) [{:(d,-b), (-c, a):}]`D. None of these |
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Answer» Correct Answer - B Given , A = `[{:(a , b) , (c , d):}]` `|A| `= ad - bc `therefore |A|^(-1) = (1)/(ad - bc)` |
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