

InterviewSolution
Saved Bookmarks
1. |
If matrix `A=[a_(ij)]_(2X2)`, where ` a_(ij)={[1,i!=j],[0,i=j]}, then A^2` is equal toA. IB. AC. 0D. none of these |
Answer» We have, `A=[a_(ij)]_(2xx2)`, where `a_(ij)=1`, if `inej=0` and if i=j `A=[{:(0,1),(1,0):}]` and `A^(2)=[{:(0,1),(1,0):}][{:(0,1),(1,0):}]=[{:(1,0),(0,1):}]=I` |
|