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    				| 1. | If `mgt1` and `ninN`, such that `1^(m)+2^(m)+3^(m)+...+n^(m)gtn((n+1)/(k))^(m)` Then, k=A. 2B. nC. mD. 1 | 
| Answer» Correct Answer - A For `mgt1,` we have `A.M. "of mth powers"gt"mth power of "A.M.` `:." "(1^(m)+2^(m)+3^(m)+...+n^(m))/(n)gt((1+2+3...+n)/(n))^(m)` `implies" "(1^(m)+2^(m)+3^(m)+n^(m))/(n)gt((n+1)/(2))^(m)` `implies" "1^(m)+2^(m)+...+n^(m)gtn((n+1)/(2))^(m)` Hence, k=2. | |