1.

If minimum deviation is delta_m, for prism then refractive index of material of prism is ......

Answer»

`MU=(SIN(A+deltam))/((2)/(SINA//2))`
`mu=(sin((A+deltam)/(2)))/(sinA//2)`
`mu=(2SIN(A+deltam))/(sinA)`
`mu=(sin(A+deltam))/(sinA)`

Solution :`mu=(sin((A+deltam)/(2)))/(sinA//2)`


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