1.

If molarity = molality and density of the solution is 2gm/ml thenW_("solute"):W_("solvent") would be

Answer»

`1:2`
`2:1`
`1:1`
`1:3`

Solution :`:.` Given that
Molarity =molality
`("moles")/(V(sdn)(L))=("moles")/(W("SOLVENT")(kg))`
`IMPLIES W_(("solvent"))` is numerically EQUAL to volume of the solution.
`V_(("so In"))=(W("solution"))/(d("solution"))implies(w("solution"))/(d("solution"))=W` (solvent)
`((W_("solution"))/(W_("solvent"))-d_("solution"))`
As `d=2` gm/ml
`impliesW_("solution")=2W_("solvent")impliesW_("solute")=W_("solvent")`


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