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If momentum of alpha,beta and gamma waves is equal then which out of these will have maximum wavelength? |
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Answer» ALPHA rays `P=(hf)/(c )` For photon `lambda=(H)/(p)` (de-Broglie wavelength) If momentum of both is equal then de-Broglie wavelength also will be equal `alpha` and `Beta` particle have equal de-Broglie wavelength and photon (`gamma`-rays) can be considered having equal wavelength. |
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