1.

If mu_(0) is permeability of free space and epsilon_(0) is permittivity of free space , the speed of light in vacuum is given by

Answer»

`sqrt((1)/(mu_(0)epsilon_(0)))`
`sqrt((epsilon_(0))/(mu_(0)))`
`sqrt(mu_(0)epsilon_(0))`
`sqrt((mu_(0))/(epsilon_(0)))`

SOLUTION :The VELOCITY of light `c=(1)/(sqrt(mu_(0)epsilon_(0)))`


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