1.

If `N_(0)` is the original mass of the substance of half - life period `t_(1//2) = 5 year` then the amount of substance left after `15` year isA. `(N_(0))/(8)`B. `(N_(0))/(16)`C. `(N_(0))/(2)`D. `(N_(0))/(4)`

Answer» Correct Answer - A
`N/N_(0)=(1/2)^(n)` where n are is number of half-lives. If `T_(1//2)=5` years then in `15` years, `n=3`
`implies N/N_(0)=(1/2)^(3)=1/8 implies N=N_(0)/8`


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