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If `n >1`, the value of the positive integer `m`for which `n^m+1`divides `a=1+n+n^2+ddot+n^(63)`is/are`8`b. `16`c. `32`d. `64`A. 8B. 16C. 32D. 64 |
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Answer» Correct Answer - A::B::C `a=(n^(64)-1)/(n-1)` `=(n+1)(n^(2)+1)(n^(4)+1)(n^(8)+1)(n^(16)+1)(n^(32)+1)` |
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