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If N_(2) gas is bubbled through water at 293 K, how many millimoles of N_(2) gas would dissolve in 1 litre of water ? Assume that N_(2) exerts a partial pressure of 0.987 bar. Given that Henry's law constant for N_(2) at 298 K is 76.48 kbar. |
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Answer» <P> Solution :`"According to Henry's law, "p_(N_(2))=K_(H)xxx_(N_(2)), thereforex_(N_(2))=(p_(N_(2)))/(K_(H))=("0.987 bar")/("76480 bar")=1.29xx10^(-5)`If N moles of `N_(2)` are prsent in 1 L of water (i.e., 55.5 moles), `x_(N_(2))=(n)/(n+55.5)~=(n)/(55.5)("as "ltlt 55.5)` `therefore""(n)/(55.5)=1.29xx10^(-5)"or"n=1.29xx10^(-5) xx 55.5" moles"=71.595xx10^(-5)" moles = 0.716 MILLIMOLES"` |
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