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If n(A) = 2 and n(B ∪ C) = 3, then n[(A × B) ∪ (A × C)] is …..(a) 23(b) 32 (c) 6 (d) 5 |
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Answer» (c) 6 n[(A × B) ∪ (A × C)] = n[ A × (B ∪ C)] = n(A) × n(B ∪ C) = 2 × 3 = 6 |
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