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If n(A)=25, n(B)=40, n(AᴜB)=50 and n(B´)=25 find n(A∩B) |
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Answer» Step-by-step explanation:Here's the ANSWER!Given : n(A) = 25; n(B) = 40 ; n (AUB) = 50; n (B¹) = 25Formula to be used: n (AUB) = n(A) + n (B)-n (ANB)Substituting the given values in the above formula we get,=> 50 = 25 + 40-n (ANB)=> n(ANB) = 25+ 40 - 50=> n(ANB) = 65-50 = 15Hence n (ANB) = 15We also know that,n (B¹) = n(U) - n (B) Substituting the values we get,25=n(U)- 40=n(U)= 40+ 25 = 65.Hence the universal set n (U) CONTAINS 65 elements.Hope it helped ! |
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