InterviewSolution
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InterviewSolution
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If `n`biscuits are distributed among `N`beggars, find the chance that a particular beggar will get `r(A. `((N-1)^(n-r))/(N^(n))`B. `(.^(n)C_(r ))/(N^(n-r))`C. `(.^(n)C_(r )(N-1)^(r ))/(N^(n))`D. `(.^(n)C_(r )(N-1)^(n-r))/(N^(n))` |
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Answer» Correct Answer - D Since a biscuit can be given to any one of N beggars. Therefore, each biscuit can be distributed in N ways. So, the total number of ways of distributing n biscuits among N beggars is `N xx N xx ..xx N=N^(n)` n-times Now, r biscuits can be given to a particular beggar in `.^(n)C_(r )` ways and the remaining (n-r) biscuits can be distributed to (N-1) beggars in `(N-1)^(n-r)` ways. Thus, the number of ways in which a particular beggar receives r biscuits is `.^(n)C_(r )xx(N-1)^(n-r)` Hence, required probability `=(.^(n)C_(r )xx(N-1)^(n-r))/(N^(n))` |
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