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If `n in N`, then `121^n- 25^n + 1900^n – (-4)^n` is divisible byA. 1904B. 2000C. 2002D. 2006 |
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Answer» Correct Answer - B n `in` N, `121^(n)-25^(n)+1900^(n)-(-4^(n))` Let us substitute n = 1 We get, `(121)^(1)-(25)^(1)+(1900)^(1)-(-4^(1))` `=121 - 25 + 1900 + 4 `=2025 - 25` `=2000` So, given expression is divisible by 2000 |
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