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If N Is A Natural Number, Then (7(n2) + 7n) Is Always Divisible By: |
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Answer» (7n2 + 7N) = 7n(N + 1), which is always divisible by 7 and 14 both, since n(n + 1) is always EVEN. (7n2 + 7n) = 7n(n + 1), which is always divisible by 7 and 14 both, since n(n + 1) is always even. |
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