1.

If n is a natural number, then 92n − 42n is always divisible by(a) 5(b) 13(c) both 5 and 13(d) None of these[Hint : 92n − 42n is of the form a2n − b2n which is divisible by both a − b and a + b. So, 92n − 42n is divisible by both 9 − 4 = 5 and 9 + 4 = 13.]

Answer» If n is a natural number, then 92n − 42n is always divisible by



(a) 5

(b) 13

(c) both 5 and 13

(d) None of these



[Hint : 92n − 42n is of the form a2n − b2n which is divisible by both a − b and a + b. So, 92n − 42n is divisible by both 9 − 4 = 5 and 9 + 4 = 13.]


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