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InterviewSolution
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if n is the smallest natural number such that `n+2n+3n+* * * * * * *+99n` is a perfect squre , then the number of digits in `n^(2)` is -A. 1B. 2C. 3D. more than 3 |
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Answer» Correct Answer - C `n+2n+3n+** *+99n=k^(2)` `implies n(99.100)/(2)=k^(2) ` `implies n.99.50=k^(2)` `implies n.9.11.25.2=k^(2)` SO n=11.2=22 `n^(2) =484` No .of digits in `n^(2)`=3 . |
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