1.

If NaCl is doped with 10^(4) mol % of SrCl_(2) the concentration of cation vacancies will be (N_(A) = 6.02 xx 10^(23) mol^(-1))

Answer»

`6.02 xx10^(16) MOL^(-1)`
`6.02 xx10^(17) mol^(-1)`
`6.02 xx10^(14) mol^(-1)`
`6.02 xx10^(15) mol^(-1)`

Answer :B


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