If `omega(!=1)`is a cube root of unity,and `(1""+omega)^7=""A""+""Bomega`. Then (A, B) equals(1) (0, 1) (2) (1, 1) (3) (1, 0) (4) `(-1,""1)`A. 0,1B. 1,1C. 1,2D. `-1,1`

If `omega(!=1)`is a cube root of unity,and `(1""+omega)^7=""A""+""Bome

1.	If `omega(!=1)`is a cube root of unity,and `(1""+omega)^7=""A""+""Bomega`. Then (A, B) equals(1) (0, 1) (2) (1, 1) (3) (1, 0) (4) `(-1,""1)`A. 0,1B. 1,1C. 1,2D. `-1,1`
Answer» Correct Answer - B `(1+omega)^7=(1+omega)(1+omega)^6` `=(1+omega)(-omega^2)^6=1+omega` `rArr " "A+Bomega=1+omega` `rArr" "A=1,B=1`

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If `omega(!=1)`is a cube root of unity,and `(1""+omega)^7=""A""+""Bomega`. Then (A, B) equals(1) (0, 1) (2) (1, 1) (3) (1, 0) (4) `(-1,""1)`A. 0,1B. 1,1C. 1,2D. `-1,1`

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