If `omega(!=1)`is a cube root of unity,and `(1+omega)^7= A + B omega`. Then (A, B) equalsA. `(-1,1)`B. `(0,1)`C. `(1,1)`D. `(1,0)`

If `omega(!=1)`is a cube root of unity,and `(1+omega)^7= A + B omega`.

1.	If `omega(!=1)`is a cube root of unity,and `(1+omega)^7= A + B omega`. Then (A, B) equalsA. `(-1,1)`B. `(0,1)`C. `(1,1)`D. `(1,0)`
Answer» Correct Answer - C `(1+ omega)^(7) = A + Bomega ` ` therefore (-omega^(2))^(7) = A + Bomega` `therefore -omega^(2) = A Bomega ` `therefore 1+ omega = A + Bomega ` `therefore A = 1 , B = 1` ` therefore (A,B) = (1,1)`

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If `omega(!=1)`is a cube root of unity,and `(1+omega)^7= A + B omega`. Then (A, B) equalsA. `(-1,1)`B. `(0,1)`C. `(1,1)`D. `(1,0)`

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