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If one mole of a monatomic gas `(gamma=5/3)` is mixed with one mole of a diatomic gas `(gamma=7/5),` the value of gamma for mixture isA. 1.4B. 1.5C. 1.53D. 3.07 |
Answer» Correct Answer - b (b) `{:(C_(v)=(3)/(2)RT),(C_(p)=(5)/(2)RT):}` for monoatomic gas, `{:(C_(v)=(5)/(2)2RT),(C_(p)=(7)/(2)RT):}` for diatomic gas Thus, for mixture for 1 mole each, `C_(v)=((3)/(2)RT+(5)/(2)RT)/(2)` `and" "C_(p)=((5)/(2)RT+(7)/(2)RT)/(2)` Thus, `(C_(p))/(C_(v))=(3RT)/(2RT)=1.5` |
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