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If one mole of a monoatomic gas gamma =(5)/(3), is mixed with one mole of diatomic gas gamma =(7)/(5), what is the value of gamma for the mixture ? |
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Answer» `(3)/(2)` Average `C_(p) =C_(v)+R =2R +R =3R` `therefore" Average "GAMMA =(3R)/(2R) =(3)/(2) =1.5` `therefore` Correct choice is (a). |
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