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If one number is randomly selected between 1 and 20, what is the probability that the number is a multiple of 5 ?(a) \(\frac{1}{2}\)(b) \(\frac{1}{6}\)(c) \(\frac{1}{5}\)(d) \(\frac{1}{3}\) |
Answer» P(E) = Favourable outcomes/ total no. of possible outcomes here, favourable outcomes are 5,10,15,20... So P(multiple of 5) = 4/20 = 1/5 So, the answer is (c) 1/5. Correct option is (c) \(\frac{1}{5}\) |
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