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If one of the two electrons of a H_(2) molecule is removed, we get a hydrogen molecular ion H_(2)^(+). In the ground state of an H_(2)^(+), the two protons are separated by roughly 1.5Å, and the electron is roughly 1Å from each proton. Determine the potential energy of the system. Specific your choice of the zero of potential energy. |
Answer» Solution : `U=U_(1)+U_(2)+U_(3) ""U_(1)=(9 XX 10^(9) E^(2))/(1.5 xx 10^(-10)) U_(2)=U_(3)` `U_(2)+U_(3)=(9 xx 10^(9) xx -2E^(2))/(1 xx 10^(-10))` `U=(9 xx 10^(9) e^(2))/(10^(10)) (1/(1.5) -2/1)=(9 xx 10^(9) xx (1.6)^(2) xx 10^(38) xx -2)/(10^(-10) xx 1.5 xx 1.6 xx 10^(-19))eV` `=(-9 xx 1.6 xx 2)/(1.5) =(-9 xx 16 xx 4)/(30)=-19.2eV` |
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