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If one root of the equation `z^2-a z+a-1=0i s(1+i),w h e r ea`is a complex number then find the root. |
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Answer» Correct Answer - z=1 `z^(2) -az + a 1 =0` Putting z = 1 + i a=2+i `rArr z^(2) - (2+i)z + 1 + i=0` is the equaiton `rArr z = 1` is the other roots |
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