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If one root of the quadratic equation `ix^2-2(i+1)x +(2-i)=0,i =sqrt(-1)` is `2-i`, the other root isA. `3+i`B. `3+sqrt(-1)`C. `-1+i`D. `-1-i` |
Answer» Correct Answer - D Since all the coefficients of given equation are not real. Therefore, other root `!=3+i` Let other root be `alpha`. Then sum of the roots`=(2(1+i))/i` `impliesalpha+3-i=(2(1+i))/i` `impliesalpha+3-i=2-2i` `:.alpha=-1-i` |
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