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If onemole monoatmic ideal gas was taken through process AB as shown is figure , then select correcgtoption(s). Given: In 1.5 = 0.4

Answer»

`W_(AB)= - 1496.52 J`
`q_(AB)=5237.82 J`
`DeltaH_(AB) = 3741.3 J`
`DeltaS_(AB) "is + ve"`

Solution :(a)`"y = mx" + C`
`10 = mm xx 300 + C`
`15 = mxx 600+ C`
`5 = 300 m`
`m = (1)/(60), "" c= 5`
`V=(1)/(60) T + 5""w = - int PDeltaV`
`P = 60 R - (300R)/(V)`
` w = -.^(15)int_(10) (60R-(300R)/(V))DV =- 1496.52J`
(b)`DELTAU= q + w or q= DeltaU-w`
`DeltaU= C_(V) DeltaT =374 .13`
`q = 374.13 + 1496.525 = 5237. 82 J`
(c)`Deltah = (5)/(2) xx Rxx 300 `
(d) `DeltaS = + ve`


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