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If (P,0) is a point on x axis which is equidistant from the point (5,-2) and (-3,2) , then find P |
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Answer» et the point on the X−axis be P(a,0)Let the other two point be A(−2,5) and B(2,−3)So by distance formula we have,Distance between two points = (x 2 −x 1 ) 2 +(y 2 −y 1 ) 2 Then,PA=PBPA 2 =PB 2 ⇒(a+2) 2 +(0−5) 2 =(a−2) 2 +(0+3) 2 ⇒a 2 +4+4a+25=a 2 +4−4a+9⇒4a+29=−4a+13⇒ 8a=−16⇒a=−2∴ The required point isP(−2,0) PLEASE mark me as brainliest |
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