1.

If p - 1,p+ 1 ,3p -1 are in AP then P is equal ​

Answer»

Step-by-step EXPLANATION:

a1 = p - 1

a2 = p + 1

A3 = 3p - 1

Common difference is same EVERYWHERE , so ,

a2 - a1 = a3 - a2

⇒

2( a2 ) = a3 + a1

∴ a2 = (a3 + a1) / 2

⇒

p + 1 = (p - 1 + 3p - 1) / 2

p + 1 = (4p - 2) / 2 = 2p - 1

p + 1 = 2p - 1

1 + 1 = p

∴ p = 2

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