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If p.d. across a capacitor is doubled b. halved, by what factor does the energy stored change in each case? |
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Answer» Solution :`E=1/2 CV^(2)` a. `triangleE=(1/2 C(2V)^(2))/(1/2 CV^(2)) =4"TIMES"` b. `triangleE=(1/2 C(V/2)^2)/(1/2 CV^(2))=1/4` |
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