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If 'P' is the middle point on the axis of a solenoid then derive the expression for magnetic field at that point. |
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Answer» <P> Solution :`""costheta=(L/2)/sqrt(r^(2)+l^(2)/4)""(##SPH_ABT_PHY_QB_XII_C04_E03_001_S01.png" width="80%">i.e., `""costheta=l/2 times 2/sqrt(4r^(2)+l^(2))=l/sqrt(4r^(2)+l^(2))` here `""B_(p)=(mu_(0)/(4PI))((2pini)/l)(2costheta)` i.e., `""B_(p)=mu_(0)Ni(l/sqrt(4r^(2)+l^(2)))=(mu_(0)NIL)/sqrt(4r^(2)+l^(2)) " where " N=n/l` `therefore ""B_(p)=(mu_(0)ni)/sqrt(4r^(2)+l^(2))` |
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