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    				| 1. | If P(n) is the statement “2n ≥ 3n”, and if P(r) is true, prove that P(r + 1) is true. | 
| Answer» Given. P(n) = “2n ≥ 3n” and p(r) is true. Prove. P(r + 1) is true we have P(n) = 2n ≥ 3n Since, P(r) is true So, = 2r ≥ 3r Now, Multiply both side by 2 = 2.2r ≥ 3r.2 = 2r+1 ≥ 6r = 2r+1 ≥ 3r + 3r [since 3r >3 = 3r + 3r ≥3 + 3r] Therefore 2r+1 ≥ 3(r + 1) Hence, P(r + 1) is true | |