1.

If P(n) is the statement “2n ≥ 3n”, and if P(r) is true, prove that P(r + 1) is true.

Answer»

Given. 

P(n) = “2n ≥ 3n” and p(r) is true. 

Prove. P(r + 1) is true 

we have P(n) = 2n ≥ 3n 

Since, P(r) is true So, 

= 2r ≥ 3r 

Now, Multiply both side by 2 

= 2.2r ≥ 3r.2 

= 2r+1 ≥ 6r 

= 2r+1 ≥ 3r + 3r [since 3r >3 = 3r + 3r ≥3 + 3r] 

Therefore 2r+1 ≥ 3(r + 1) 

Hence, P(r + 1) is true



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